Q:

Suppose the time it takes for a purchasing agent to complete an online ordering process is normally distributed with a mean of 8 minutes and a standard deviation of 2 minutes. Suppose a random sample of 25 ordering processes is selected. What is the standard deviation of the sampling distribution of mean​ times? (Round to one decimal place.)

Accepted Solution

A:
Answer:  0.4Step-by-step explanation:We know that the standard deviation of the sampling distribution of mean​ is given by:-[tex]\sigma_x=\dfrac{\sigma}{\sqrt{n}}[/tex]Given : Standard deviation : [tex]\sigma= 2\text{ minutes}[/tex]Sample size : n= 25Then, the standard deviation of the sampling distribution of mean​ times will be :-[tex]\sigma_x=\dfrac{2}{\sqrt{25}}\\\\\Rightarrow\ \sigma_x=\dfrac{2}{5}=0.4[/tex]Hence, the standard deviation of the sampling distribution of mean​ times=0.4