On a single roll of a pair of dice, what are the odds against rolling a sum of 12?

Answer:[tex]\frac{1}{35}[/tex]Step-by-step explanation:On a single roll of a pair of dice. When a pair of dice are rolled the possible outcomes are as follows:(1,1)         (1,2)          (1,3)  (1,4)  (1,5)  (1,6)(2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)(3,1)  (3,2)  (3,3)  (3,4)  (3,5)  (3,6)(4,1)  (4,2)  (4,3)  (4,4)  (4,5)  (4,6)(5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)(6,1)  (6,2)  (6,3)  (6,4)  (6,5)  (6,6) The number of outcomes that gives us 12 are (6,6). There is only one outcome that gives us sum 12.Total outcomes = 36Odd against favor = [tex]\frac{non \ favorable\ outcomes}{favorable \ outcomes}[/tex]Number of outcomes of getting sum 12 is 1Number of outcomes of not getting sum 12 is 36-1= 35odds against rolling a sum of 12= [tex]\frac{1}{35}[/tex]